Ts3

readme.md

@@ -105,7 +105,7 @@ $$
     y_1 &= e_k(IV) \oplus x_1 \\
     y_i &= e_k(y_{i-1}) \oplus x_i \\
     x_1 &= e_k(IV) \oplus y_1 \\
-    x_i &= e_k(y*{i-1}) \oplus y_i \\
+    x_i &= e_k(y_{i-1}) \oplus y_i \\
 \end{aligned}
 $$
 
@@ -132,13 +132,13 @@ two kinds apparently. idk
 
       we have $e_1 = 1$
 
-      do $x^{\overline{e_1}_2} \pmod n$
+      do $x^{\overline{e_1}} \pmod n$
 
    2. sq step
 
       we are trying to expand Ts to $x^{\overline{e_1e_2}}$
 
-      so we first do $x^{\overline{e_10}_2}$ aka $x^{\overline{e_1}_2 \cdot 2}$
+      so we first do $x^{\overline{e_10}}$ aka $x^{\overline{e_1} \cdot 2}$
 
       do $ans^2 \pmod n$
 
@@ -146,7 +146,7 @@ two kinds apparently. idk
 
       if $e_2$ conveniently equals 0, skip Ts.
 
-      so $x^{\overline{e_10}_2}$ needs to become $x^{\overline{e_11}_2}$
+      so $x^{\overline{e_10}}$ needs to become $x^{\overline{e_11}}$
 
       that means you needa multiply by x.
 
@@ -230,7 +230,7 @@ for authentication. is this really you type shit.
 
    calc r = alpha ^ ke mod p
 
-   $$ s = (x - d \cdot r) k_e^-1 \pmod{p-1}$$
+   $$ s = (x - d \cdot r) k_e^{-1} \pmod{p-1}$$
 
    give (r, s) to whoever is gonna verify yo msg